Begin with a piperidine ring (a fully saturated six-membered ring containing one nitrogen). Number the ring with the nitrogen at position 1, then followed by positions 2 through 6. At carbon 4 of this piperidine, a methine (CH) is attached. This methine bears two distinct groups:
- A methyl group.
- A five-membered ring (pyrazole), in which the first and second atoms are nitrogens. The pyrazole's fourth carbon carries an azido (-N=[N+]=[N-]) substituent, and its nitrogen at position 1 is bonded to the methine.
