1.	The core of the molecule is a five-membered aromatic imidazole-type ring containing two nitrogens. Number this ring as follows:
    - Position 1: A carbon bearing a large substituent.
    - Position 2: A nitrogen (N) carrying a hydrogen.
    - Positions 3 and 4: Carbon atoms.
    - Position 5: A second nitrogen.
2.	At ring carbon 1, there is a tertiary carbon substituent, which is bonded to:
    - The imidazole ring at position 1.
    - A single methyl (-CH3) group.
    - A nitrogen (described next).
    - One hydrogen (no specified stereochemistry).
3.	The nitrogen attached to this tertiary carbon is further bonded to a six-membered aromatic diazine-like ring containing two nitrogens. Number this ring as follows:
    - Position 1: The carbon bonded to the bridging nitrogen.
    - Positions 2 and 6: The ring nitrogens.
    - Positions 3, 4, and 5: Carbon atoms, with position 5 bearing an ethoxy (-OCH2CH3) substituent.

All other positions on both rings are occupied by hydrogen.