1. Start with a benzene ring bearing a single substituent on one ring carbon.
2. This substituent is a 1H-imidazole ring (N1-C2-N3-C4-C5) attached via its C5; in the imidazole, N1 bears a hydrogen.
3. The only other substitution on the imidazole is at C2, where a methylene (-CH2-) connects to a tertiary nitrogen.
4. This tertiary nitrogen carries three substituents:
   - The just-mentioned methylen from the imidazole.
   - A methyl group (-CH3).
   - A carbonyl which linked to a methylene, which is in turn connected through an oxygen to a phenyl ring. The phenyl ring bears a single formyl (-CH=O) substituent at meta position.
