Begin with a two-carbon chain: C1 is a methyl group; C2 is double-bonded to an oxygen (forming a carbonyl group). C2 is also bonded to a thiophene ring (five-membered, four carbons plus one sulfur), and C2 is connected to the carbon atom adjacent to the sulfur atom. On the other adjacent carbon of the sulfur atom, there is a fused bicyclic system containing three nitrogen atoms. This bicyclic system consists of a fused five- and six-membered ring. The five-membered ring is an imidazole ring (clockwise numbering as C1, C2, N3, C4, N5), and the six-membered ring contains four carbons and two adjacent nitrogen atoms (clockwise numbering as C4, C6, C7, C8, N9, N5), meaning that C4 and N5 are the shared atoms between the two rings. C1 is connected to the aforementioned thiophene ring. The nitrogen atom at position N9 bears a hydrogen, while C8 forms a double bond with an imine nitrogen (N-alpha). This N-alpha is connected via a three-methylene chain to a tertiary amine nitrogen. The tertiary amine carries a methyl group and is linked to a side chain (-C(=O)O-tBu) that forms a tert-butyl carbamate moiety.