1. Start with a piperidine ring (six-membered, fully saturated, with nitrogen at position 1).

2. The ring nitrogen (N-1) forms a sulfonamide:  
   - N-1 is bonded to a sulfonyl group, S(=O)2. 
   - The sulfur is connected to a phenyl ring through a methylene (-CH2-) linker.
   - The phenyl ring carries a single fluorine substituent ortho to the methylene linker.

3. At carbon 4 of the piperidine ring (para to the ring nitrogen), attach an enol-type amide substituent:
   - The ring carbon is bonded to a carbon bearing a hydroxyl group (-OH) and a double bond to a nitrogen (N-2).
   - N-2 is further substituted with a two-carbon chain terminating in an unsubstituted phenyl ring (-N-CH2-CH2-Ph).

4. No additional substituents, chiral centers, or specified E/Z geometry are present.