1. Start with benzene ring A.
One carbon of ring A is linked to another benzene ring B through a methyleneoxy bridge (-O-CH2-). In this linkage, the methylene carbon is directly bonded to ring A, and the oxygen atom is directly bonded to ring B.

2. On ring B.
At the meta position relative to the methyleneoxy attachment, ring B carries an ether linkage (-O-) that connects to another benzene ring (ring C).

3. On ring C.
At the para position relative to the ether attachment, ring C carries a 1H-tetrazole ring (ring D). The tetrazole is a five-membered aromatic heterocycle with four nitrogens; In ring D, its only carbon atom is connected to the benzene ring C through a methylene group.